4(2cos^2x-1)+3cosx=1

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Solution for 4(2cos^2x-1)+3cosx=1 equation:


Simplifying
4(2cos2x + -1) + 3cosx = 1

Reorder the terms:
4(-1 + 2cos2x) + 3cosx = 1
(-1 * 4 + 2cos2x * 4) + 3cosx = 1
(-4 + 8cos2x) + 3cosx = 1

Reorder the terms:
-4 + 3cosx + 8cos2x = 1

Solving
-4 + 3cosx + 8cos2x = 1

Solving for variable 'c'.

Move all terms containing c to the left, all other terms to the right.

Add '4' to each side of the equation.
-4 + 3cosx + 4 + 8cos2x = 1 + 4

Reorder the terms:
-4 + 4 + 3cosx + 8cos2x = 1 + 4

Combine like terms: -4 + 4 = 0
0 + 3cosx + 8cos2x = 1 + 4
3cosx + 8cos2x = 1 + 4

Combine like terms: 1 + 4 = 5
3cosx + 8cos2x = 5

Reorder the terms:
-5 + 3cosx + 8cos2x = 5 + -5

Combine like terms: 5 + -5 = 0
-5 + 3cosx + 8cos2x = 0

The solution to this equation could not be determined.

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